Difference between revisions of "Math Diagnostic"

From SFU_Public
Jump to: navigation, search
Line 48: Line 48:
  
 
<math>\left \uparrow \frac{a}{b} \right \downarrow \quad \left \Uparrow \frac{a}{b} \right \Downarrow \quad \left \updownarrow \frac{a}{b} \right \Updownarrow</math>
 
<math>\left \uparrow \frac{a}{b} \right \downarrow \quad \left \Uparrow \frac{a}{b} \right \Downarrow \quad \left \updownarrow \frac{a}{b} \right \Updownarrow</math>
 +
 +
*Making this assumption gives <math>1/\tau(\omega) = 1/\tau_0 + \kappa\omega^2/2 \approx 1/\tau_0 \lambda_0\omega^2/\omega_\lambda \Rightarrow \omega_\lambda = 2\lambda_0/\kappa,</math> so that:<math>\lambda(\omega,T) = \frac{\lambda_0}{1 + (\kappa\omega/2\lambda_0)^2 + (T/T_\lambda)^2}.</math>

Revision as of 20:44, 14 April 2016

hello




  • Making this assumption gives so that: